projecteuler Smallest multiple

2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.

What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?

 

译:

2520是能被从1到10整除的最小整数,求出能被从1到20整除的最小数。

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第一次code:

 1 public class Main
 2 {  
 3      public static void main (String[] args) 
 4      {     
 5         System.out.println(sum(600000000)); 
 6      }   
 7      public static int sum(int num)
 8      {
 9       int c=0;
10       for(int i=1;i<num;i++)
11       {
12           if(i % 1== 0 && i % 2 ==0
13           && i % 3== 0 && i % 4 ==0
14           && i % 5== 0 && i % 6 ==0
15           && i % 7== 0 && i % 8 ==0
16           && i % 9== 0 && i % 10 ==0
17           && i % 11== 0 && i % 12 ==0
18           && i % 13== 0 && i % 14 ==0
19           && i % 15== 0 && i % 16 ==0
20           && i % 17== 0 && i % 18 ==0
21           && i % 19== 0 && i % 20 ==0
22                   )
23           {
24               c=i;
25               break;
26           }
27           else
28           {
29               c=111;
30           }
31        }
32        return c;
33      }
34 }
原文地址:https://www.cnblogs.com/niithub/p/5799298.html