【NOIP2012模拟8.9】逐个击破

(Code)

#include<cstdio>
#include<algorithm>
using namespace std;
int vis[100005],n,m,fa[100005];

struct nd{
	int l,r,v;
}a[100005];
bool cmp(nd x,nd y){return x.v > y.v;}
int find(int x)
{
	if (x != fa[x]) fa[x] = find(fa[x]);
	return fa[x];
}
int merge(int x,int y)
{
	int t1,t2;
	t1 = find(x);
	t2 = find(y);
	if (vis[t1] && vis[t2]) return 0;
	if (vis[fa[t1]]) fa[t2] = fa[t1];
	else fa[t1] = fa[t2];
	return 1;
}
int main()
{
	scanf("%d%d",&n,&m);
	for (int i = 1; i <= m; i++)
	{
		int q;
		scanf("%d",&q);
		vis[q + 1] = 1;
	}
	long long sum = 0,ans = 0;
	for (int i = 1; i < n; i++)
		scanf("%d%d%d",&a[i].l,&a[i].r,&a[i].v),sum += (long long)a[i].v;
	sort(a + 1,a + n,cmp);
	for (int i = 1; i <= n; i++) fa[i] = i;
	for (int i = 1; i < n; i++)
		if (merge(a[i].l + 1,a[i].r + 1))
			ans += (long long)a[i].v;
	printf("%lld",sum - ans);
}
原文地址:https://www.cnblogs.com/nibabadeboke/p/13776243.html