HDOJ 1083 Hungarian实现

 1 #include<cstdio>
 2 #include<vector>
 3 
 4 using namespace std;
 5 
 6 #define N1 100
 7 #define N2 300
 8 
 9 int match[N2];
10 vector<int> graph[N1];
11 bool visit[N2];
12 
13 bool hungarian(int u){
14     for (auto i = graph[u].begin(); i != graph[u].end(); i++)
15         if (!visit[*i]){
16             visit[*i] = 1;
17             if (match[*i] == -1 || hungarian(match[*i])){
18                 match[*i] = u;
19                 return true;
20             }
21         }
22     return false;
23 }
24 
25 int main(){
26     int m;
27     scanf("%d", &m);
28     for (int i = 0; i < m; i++){
29         int p, n;
30         bool flag = 0;
31         scanf("%d %d", &p, &n);
32         for (int j = 0; j < p; j++){
33             int num;
34             scanf("%d", &num);
35             graph[j].clear();
36             for (int l = 0; l < num; l++){
37                 int student;
38                 scanf("%d", &student);
39                 graph[j].push_back(student - 1);
40             }
41         }
42         for (int j = 0; j < n; j++)
43             match[j] = -1;
44         for (int j = 0; j < p; j++){
45             for (int l = 0; l < n; l++)
46                 visit[l] = 0;
47             if (!hungarian(j)){
48                 flag = 1;
49                 break;
50             }
51         }
52         if (flag)
53             printf("NO
");
54         else
55             printf("YES
");
56     }
57     return 0;
58 }