python集合关系

list_1 = [1,4,5,7,3,6,7,9]
list_1 = set(list_1)

list_2 =set([2,6,0,66,22,8,4])
print(list_1,list_2)
'''
#交集
print(  list_1.intersection(list_2) )

#并集
print(list_1.union(list_2))

#差集 in list_1 but not in list_2
print(list_1.difference(list_2))
print(list_2.difference(list_1))

#子集
list_3 = set([1,3,7])
print(list_3.issubset(list_1))
print(list_1.issuperset(list_3))




#对称差集
print(list_1.symmetric_difference(list_2))


print("-------------")

list_4 = set([5,6,7,8])
print(list_3.isdisjoint(list_4)) # Return True if two sets have a null intersection.
'''


#交集
print(list_1 & list_2)
#union
print(list_2 | list_1)

#difference
print(list_1 - list_2) # in list 1 but not in list 2

#对称差集
print(list_1 ^ list_2)

list_1.add(999)
list_1.update([888,777,555])
print(list_1)

print(list_1.pop())
print(list_1.pop())
print(list_1.pop())
print(list_1.pop())

print(  list_1.discard(888)  )
原文地址:https://www.cnblogs.com/ne-zha/p/7245540.html