小小的模拟一下。
1 #include <cstdio> 2 #include <cstring> 3 #include <string> 4 #include <cmath> 5 #include <algorithm> 6 using namespace std; 7 char str[1000]; 8 double a[10]; 9 double b[10]; 10 void CL() 11 { 12 a[0] = a[2] = 0.0; 13 a[4] = a[5] = sqrt(2.0)/2.0; 14 a[1] = 1.0; 15 a[3] = -1.0; 16 a[6] = a[7] = -sqrt(2.0)/2.0; 17 b[0] = 1.0; 18 b[2] = -1.0; 19 b[4] = b[7] = sqrt(2.0)/2.0; 20 b[3] = b[1] = 0.0; 21 b[5] = b[6] = -sqrt(2.0)/2.0; 22 } 23 int judge(int x) 24 { 25 if(str[x+1] == ','||str[x+1] == '.') 26 { 27 if(str[x] == 'N') 28 return 0; 29 else if(str[x] == 'E') 30 return 1; 31 else if(str[x] == 'S') 32 return 2; 33 else if(str[x] == 'W') 34 return 3; 35 } 36 else 37 { 38 if(str[x] == 'N'&&str[x+1] == 'E') 39 return 4; 40 else if(str[x] == 'S'&&str[x+1] == 'E') 41 return 5; 42 else if(str[x] == 'S'&&str[x+1] == 'W') 43 return 6; 44 else if(str[x] == 'N'&&str[x+1] == 'W') 45 return 7; 46 } 47 return 0; 48 } 49 int main() 50 { 51 int len,i,cas = 1,pre,j,temp; 52 double x,y; 53 CL(); 54 while(scanf("%s",str)!=EOF) 55 { 56 if(strcmp(str,"END") == 0) break; 57 len = strlen(str); 58 pre = 0; 59 x = y = 0; 60 for(i = 0; i < len; i ++) 61 { 62 if(str[i] == ','||str[i] == '.') 63 { 64 temp = 0; 65 for(j = pre; j < i; j ++) 66 { 67 if(str[j] <= '9'&&str[j] >= '0') 68 temp = temp*10 + str[j] - '0'; 69 else 70 break; 71 } 72 x += temp*a[judge(j)]; 73 y += temp*b[judge(j)]; 74 pre = i+1; 75 } 76 } 77 printf("Map #%d ",cas++); 78 printf("The treasure is located at (%.3f,%.3f). ",x,y); 79 printf("The distance to the treasure is %.3f. ",sqrt(x*x+y*y)); 80 } 81 return 0; 82 }