8、与字符串处理相关的几个程序

1、转换字符串的输入格式为：原来字符串里的字符＋该字符连续出现的个数，例如字符串：1233422222，转化为1121324125。

    我们用sprintf来实现，类同printf。

#include "iostream"
#include "string"
using namespace std;

int main() 
{
cout << "Enter the numbers: " << endl;
string str;
cin >> str;
size_t ilength = str.length();
int icount = 1;
char cMyChar[50];
cMyChar[0] = '\0';
int k;
for (k = 0; k < ilength - 1; k++)
{
if (str[k] == str[k + 1]) //预判断
{
icount++; //记录字符个数
}
else
{
sprintf(cMyChar + strlen(cMyChar), "%c%d", str[k], icount);
icount = 1;
}
}

if (str[k] == str[k - 1])
;
else
icount = 1;
sprintf(cMyChar + strlen(cMyChar), "%c%d", str[k], icount);
cout << cMyChar << endl;
return 1;
}

2、整数转换成字符串

#include "iostream"
using namespace std;
int main() 
{
	int iMyData;
	cin >> iMyData;
	char cToTransfer[56];
	char cTemp[56];
	int icount = 0; //标记位数
	while(iMyData)
	{
		cTemp[icount++] = iMyData % 10 + '0';
		iMyData = iMyData / 10;
	}
	cTemp[icount] = '\0';
	cout << cTemp << endl;
	icount--;
	int j = icount, i = 0;
	while(j >=0)
	{
		cToTransfer[i++] = cTemp[j--];
	}
	cToTransfer[i] = 0;
	cout << cToTransfer << endl;
	return 1;
}

3、字符串转换成整数

#include "iostream"
using namespace std;

int main() 
{
	char iMyData[56];
	cin >> iMyData;
	int iToTransfer[56];
	int cTemp[56];
	int icount = 0; //标记位数
    int iSum = 0;
	while(iMyData[icount])
	{
		iSum = iSum * 10 + iMyData[icount] - '0';
		icount++;
	}
	cout << iSum << endl;
	return 1;
}