很多东西只有自己动手去做了才能理解 其中的含义 呵呵 先把练手的代码贴出来以后有空了再做分析吧
本题用到下面三个关系表： CARD 借书卡: (CNO 卡号，NAME 姓名，CLASS 班级) BOOKS 图书: (BNO 书号，BNAME 书名,AUTHOR 作者，PRICE 单价，QUANTITY 库存册数 ) BORROW 借书记录: (CNO 借书卡号，BNO 书号，RDATE 还书日期 --1. 写出自定义函数，要求输入借书卡号能得到该卡号所借书金额的总和 CREATE FUNCTION GetSUMP ( @CNO int ) RETURNS int AS BEGIN declare @sum int select @sum=sum(price) from BOOKS where bno in (select bno from BORROW where cno=@CNO) return @sum END GO -- 2． 找出借书超过5本的读者,输出借书卡号及所借图书册数。 select cno,COUNT(bno) t from borrow group by cno having count(bno)>=2 -- 6． 查询现有图书中价格最高的图书，输出书名及作者。 select author,t_Books.bname from t_Books where price in (select max(price) from t_Books) -- 7． 查询当前借了"计算方法"但没有借"计算方法习题集"的读者，输出其借书卡号，并按卡号降序排序输出。 select * from borrow bb where bno= (select bno bt from t_Books where bname='计算机方法')and bb.cno not in (select cno c from borrow where bno=(select bno b from t_Books where bname='计算机方法习题集') ) order by cno desc; select cc.cno from borrow cc,t_Books dd where cc.bno=dd.bno and dd.bname='计算机方法' and not exists( SELECT * FROM BORROW aa,t_Books bb WHERE aa.BNO=bb.BNO AND bb.BNAME='计算机方法习题集' and cc.cno=aa.cno) --将"C01"班同学所借图书的还期都延长一周。 update borrow set borrow.rdate=dateadd(day,7,rdate) where cno in (select bno from borrow where cno=1) -- 9． 从BOOKS表中删除当前无人借阅的图书记录。 delete t from t_books t where not exists( select * from borrow where t.bno=bno) -- 10．如果经常按书名查询图书信息，请建立合适的索引。 create clustered index IBname on t_Books(bname) -- 11．在BORROW表上建立一个触发器，完成如下功能：如果读者借阅的书名是"数据库技术及应用"， --就将该读者的借阅记录保存在BORROW_SAVE表中（注ORROW_SAVE表结构同BORROW表）。 alter trigger trg_insert on borrow for insert,update as IF @@ROWCOUNT>0 insert borrow_save SELECT i.* FROM INSERTED i,t_books b WHERE i.BNO=b.BNO and b.bname='数据库技术及应用' insert into t_Books values('数据库技术及应用','张啊红',90.00,90) insert into borrow values(6,7,GETDATE()) --吧查询出来的数据存入指定表中 insert t_Books select bname,author,price,quantity from t_Books where bname='诛仙3' -- 12．建立一个视图，显示"01"班学生的借书信息（只要求显示姓名和书名）。 alter view v_v05 as select cc.name,tb.bname from borrow b,t_Card cc,t_Books tb where b.cno=cc.cno and tb.bno=b.bno and b.cno in(select cno c from t_Card where class='09软工5版') ---- CREATE VIEW V_VIEW AS select name,bname from t_Books,t_Card,borrow where borrow.cno=t_Card.cno and borrow.bno=t_Books.bno and class='09软工5版' select * from v_v05 select * from V_VIEW --- 13．查询当前同时借有"计算方法"和"组合数学"两本书的读者，输出其借书卡号，并按卡号升序排序输出。 select cno,COUNT(bno) from borrow bb where bb.bno in(select bno bb from t_Books where bname in ('计算机方法','组合数学')) group by cno having COUNT(bno)=2 order by cno desc --select cno,count(bno) from borrow group by cno select * from borrow where bno in (select bno from t_Books where bname='计算机方法') and cno in (select cno from borrow where bno in (select bno from t_Books where bname='组合数学')) order by cno desc --- 14、用事务实现如下功能：一个借书卡号借走某书号的书，则该书的库存量减少1， ---当某书的库存量不够1本的时候，该卡号不能借该书 alter procedure proBorrowBook ( @cno int , @bno int, @rdate date ) as begin begin transaction declare @quantity int select @quantity=quantity from t_Books where bno=@bno; insert into borrow values(@cno,@bno, dateadd(day,30, @rdate)); update t_Books set quantity=@quantity-1 where bno=@bno; if(@quantity>0 and @@error<=0) begin commit transaction print '借书成功' end else begin rollback transaction print '无库存' end end select GETDATE() exec proBorrowBook 2,1,'2013-01-08 17:46:01.160' --15、用游标实现将书号为‘80’的书本的价格提高10元 declare @bno int declare @bname varchar(30) declare @author varchar(30) declare @price numeric(10,2) declare @quantity int declare myCursor cursor for select * from t_Books open myCursor fetch next from myCursor into @bno,@bname,@author,@price,@quantity while(@@FETCH_STATUS=0) begin if(@bno=2) begin update t_Books set price=@price+100 where current of myCursor end fetch next from myCursor into @bno,@bname,@author,@price,@quantity end close myCursor deallocate myCursor
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