Product of Array Except Self

Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i].

Solve it without division and in O(n).

For example, given [1,2,3,4], return [24,12,8,6].

public class Solution {
    public int[] productExceptSelf(int[] nums) {
        int size = nums.length;
        int[] front = new int[size];
        int[] re = new int[size];
        front[0] = 1;
        for(int i=1;i<size;i++) {
            front[i] = front[i-1]*nums[i-1];
        }
        
        int mutiply = 1;
        for(int i=size-1;i>=0;i--) {
            re[i] = front[i]*mutiply;
            mutiply = mutiply*nums[i];
        }
        return re;
    }
}
原文地址:https://www.cnblogs.com/mrpod2g/p/4802906.html