Rectangle Area

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

Assume that the total area is never beyond the maximum possible value of int.

public class Solution {
    public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int rectangle1 = (A-C)*(B-D);
        int rectangle2 = (E-G)*(F-H);
        
        //若这两个矩形无交集直接返回面积和
        if(E>C||H<B||G<A||F>D) return rectangle1+rectangle2;
        
        int a = Math.min(C,G)-Math.max(A,E);//相交矩形的宽
        int b = Math.min(D,H)-Math.max(B,F);//相交矩形的高
        
        return rectangle1+rectangle2-a*b;
    }
}