uva 11728

版权声明:本文为博主原创文章,未经博主同意不得转载。

https://blog.csdn.net/u011328934/article/details/36409469

题目链接:uva 11728 - Alternate Task

题目大意:给出S,求N,要求N全部的因子和为S。

解题思路:枚举因子i,全部整除i的数和加上i。

#include <cstdio>
#include <cstring>

const int N = 1005;

int n, c[N], v[N];

void init () {
    memset(c, 0, sizeof(c));
    memset(v, -1, sizeof(v));

    for (int i = 1; i < N; i++) {
        for (int j = i; j < N; j += i)
            c[j] += i;

        if (c[i] < N)
            v[c[i]] = i;
    }
}

int main () {
    init();
    int cas  = 1;
    while (scanf("%d", &n) == 1 && n) {
        printf("Case %d: %d
", cas++, v[n]);
    }
    return 0;
}
原文地址:https://www.cnblogs.com/mqxnongmin/p/10757212.html