[BJOI2012] 算不出的等式

计算

Solution

打表后发现若 (p=q)((pq-1)/4),否则 ((p-1)(q-1)/4)

#include <bits/stdc++.h>
using namespace std;

#define int long long

int p,q;

signed main() {
    cin>>p>>q;
    if(p==q) cout<<(p*q-1)/4;
    else cout<<(p-1)*(q-1)/4;
}

原文地址:https://www.cnblogs.com/mollnn/p/12598253.html