[CF1034A] Two Rabbits

判断能否整除即可

#include <bits/stdc++.h>
using namespace std;

int x,y,a,b;

int main() {
    int t;
    ios::sync_with_stdio(false);
    cin>>t;
    while(t--) {
        cin>>x>>y>>a>>b;
        if((y-x)%(a+b)==0) cout<<(y-x)/(a+b)<<endl;
        else cout<<-1<<endl;
    }
}