python 找出两个列表的相同元素与不同元素

python 找出两个列表的相同元素与不同元素,用了以下几种方法

1. 通过set 集合
list1 = [1,2,3]  
list2=[2,3,4]
set1 = set(list1)
set2 = set(list2) 
print(set1&set2) 
{2, 3}
print(set1^set2) 
{1, 4}


2.利用for循环

'''
找出两个列表中的相同元素和不同元素。
'''

def find_diff_intwo_list(list1,list2):
    '''
    :param list1: 列表1
    :param list2: 列表2
    :return:
    '''
    same,diff=[],[]
    seq=list(set(list2))
    for i in list(set(list1)):
        if i not in list2:
            diff.append(i)
        else:
            same.append(i)
    for j in same:
        seq.remove(j)

    print("same is {},diff is {}".format(same,diff+seq))

3.利用collections集合里的方法

def find_diff_by_twolist(list1,list2):
    '''
    :param list1: 列表1
    :param list2: 列表2
    :return:
    '''
    from collections import Counter
    newli=list(set(list1)) + list(set(list2))
    count=Counter(newli)
    same, diff = [], []
    for i in count.keys():
        if(count.get(i)>=2):
            same.append(i)
        else:
            diff.append(i)
    print("same is {},diff is {}".format(same, diff))

if __name__ == '__main__':
    find_diff_intwo_list([1,2,3,5,7,7,7,98],[93,0,2,6,7,98])
    find_diff_by_twolist([1,2,3,5,7,7,7,98],[93,0,2,6,7,98])

  

原文地址:https://www.cnblogs.com/mlmy/p/13427371.html