django分页实现

from django.shortcuts import render,render_to_response
from app1 import models
from django.core.paginator import Paginator,EmptyPage,PageNotAnInteger

# Create your views here.
def schools(request):
    obj=models.School.objects.all()
    objCount=obj.count()
    paginator = Paginator(obj, 24)  # Show 25 contacts per page
    page = request.GET.get('page')
    try:
        contacts = paginator.page(page)
    except PageNotAnInteger:
        # If page is not an integer, deliver first page.
        contacts = paginator.page(1)
    except EmptyPage:
        # If page is out of range (e.g. 9999), deliver last page of results.
        contacts = paginator.page(paginator.num_pages)

    return render_to_response('schools.html', {"schools": contacts})

模板部分-------------------------

<table border="2px">
   <caption>学校表格</caption>
   <thead>
      <tr>
         <th>name</th>
         <th>city</th>
         <th>addr</th>
      </tr>
   </thead>
   <tbody>

{% for contact in schools %}
    {# Each "contact" is a Contact model object. #}
{#    {{ contact.full_name|upper }}<br />#}
         <tr>
         <td>{{ contact.name }}</td>
         <td>{{ contact.city }}</td>
         <td>{{ contact.addr }}</td>

      </tr>
{% endfor %}
</tbody>
</table>

<div class="pagination">
    <span class="step-links">
        {% if schools.has_previous %}
            <a href="?page={{ schools.previous_page_number }}">上一页</a>
        {% endif %}

        <span class="current">
            第 {{ schools.number }} 页||共 {{ schools.paginator.num_pages }}页
        </span>

        {% if schools.has_next %}
            <a href="?page={{ schools.next_page_number }}">下一页</a>
        {% endif %}
    </span>
</div>

</body>