【POJ】The Suspects(裸并查集)

并查集的模板题,为了避免麻烦,合并的时候根节点大的合并到小的结点。

#include<cstdio>
#include<algorithm>
using namespace std;
const int maxn = 33333;
int fa[maxn];
int num[maxn];
int n,m,t;
void init(){
    for(int i = 0; i < n; i++) {fa[i] = i; num[i] = 1;}
}
int find_father(int u){
    return fa[u] == u ? u : fa[u] = find_father(fa[u]);
}
int main(){
    while(scanf("%d%d",&n,&m)){
        if(!m && !n) break;
        init();
        for(int i = 0; i < m; i++){
            scanf("%d",&t);
            int x,y;
            for(int j = 0; j < t; j++){
                scanf("%d",&y);
                if(!j) x = y;
                else{
                    int fy = find_father(y);
                    int fx = find_father(x);
                    if(fy > fx) swap(fy,fx); //为了避免麻烦。统一让小的根合并到大的根
                    if(fy != fx){
                        fa[fy] = fx;
                        num[fx] += num[fy];
                    }
                }
            }
        }
        t = find_father(0);
        printf("%d
",num[t]);
    }
    return 0;
}

原文地址:https://www.cnblogs.com/mengfanrong/p/5104881.html