STL在迭代的过程,删除指定的元素

直接在Code。在 Picture

#include <iostream>
#include <list>

using namespace std;

// STL在迭代的过程中,删除指定的元素
int main()
{
	list<int> listTest;

	listTest.push_back(-1);
	listTest.push_back(-1);
	listTest.push_back(-1);
	listTest.push_back(-1);

	cout<<"list size: "<<listTest.size()<<endl;

	list<int>::iterator itList;

	for (itList=listTest.begin(); itList != listTest.end(); /*no itList++ !!*/ )
	{
		cout<<"data: "<<*itList<<endl;

		// 第一种方法
		if (*itList <= 0)
			itList = listTest.erase(itList);
		else
			++itList;
	}
	cout<<"list size: "<<listTest.size()<<endl;
	cout<<"======================================"<<endl;


	listTest.push_back(-1);
	listTest.push_back(-1);
	listTest.push_back(-1);
	listTest.push_back(1);

	cout<<"list size: "<<listTest.size()<<endl;
	
	for (itList=listTest.begin(); itList != listTest.end(); ++itList)
	{
		cout<<"data: "<<*itList<<endl;

		// 另外一种方法
		if (*itList <= 0)
			*itList = 0;		// 做个记录标志。等待迭代完进行回收
	}

	listTest.remove(0);			// 回收 0

	cout<<"list size: "<<listTest.size()<<endl;
	cout<<"======================================"<<endl;

	return 0;

}

执行结果:


版权声明:本文博主原创文章。博客,未经同意,不得转载。 http://blog.csdn.net/core__code

原文地址:https://www.cnblogs.com/mengfanrong/p/4758281.html