507. Perfect Number

We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself.

Now, given an integer n, write a function that returns true when it is a perfect number and false when it is not.

 

Example:

Input: 28
Output: True
Explanation: 28 = 1 + 2 + 4 + 7 + 14

 

Note: The input number n will not exceed 100,000,000. (1e8)

完数 = 他所有正除数(不包括他本身)之和

判断一个数是不是完数

C++(3ms):

 1 class Solution {
 2 public:
 3     bool checkPerfectNumber(int num) {
 4         if(num == 1)
 5             return false ;
 6         int sum = 1 ;
 7         for(int i = 2; i <= sqrt(num) ; i++){
 8             if (num % i == 0){
 9                 sum += i ;
10                 sum += num/i ;
11             }
12         }
13         return sum == num ;
14     }
15 };

java(15ms):

 1 class Solution {
 2     public boolean checkPerfectNumber(int num) {
 3         if(num == 1)
 4             return false ;
 5         int sum = 1 ;
 6         for(int i = 2; i <= Math.sqrt(num) ; i++){
 7             if (num % i == 0){
 8                 sum += i ;
 9                 sum += num/i ;
10             }
11         }
12         return sum == num ;
13     }
14 }
原文地址:https://www.cnblogs.com/mengchunchen/p/7864985.html