242. Valid Anagram

Given two strings s and t, write a function to determine if t is an anagram of s.

For example,
s = "anagram", t = "nagaram", return true.
s = "rat", t = "car", return false.

Note:
You may assume the string contains only lowercase alphabets.

Follow up:
What if the inputs contain unicode characters? How would you adapt your solution to such case?

判断一个串的字母打乱顺序后,是否等于另一个串

C++(12ms):

 1 class Solution {
 2 public:
 3     bool isAnagram(string s, string t) {
 4         if (s.size() != t.size())
 5             return false ;
 6         vector<int> vec(128,0) ;
 7         for(char c : s){
 8             vec[c-'a']++ ;
 9         }
10         for(char c : t){
11             if (--vec[c-'a'] < 0)
12                 return false ;
13         }
14         return true ;
15     }
16 };
原文地址:https://www.cnblogs.com/mengchunchen/p/7772438.html