n 个骰子的点数

把 n 个骰子仍在地上,求点数和为 s 的概率。

java:

 1 public List<Map.Entry<Integer, Double>> dicesSum(int n) {
 2     final int face = 6;
 3     final int pointNum = face * n;
 4     long[][] dp = new long[n + 1][pointNum + 1];
 5 
 6     for (int i = 1; i <= face; i++)
 7         dp[1][i] = 1;
 8 
 9     for (int i = 2; i <= n; i++)
10         for (int j = i; j <= pointNum; j++)     /* 使用 i 个骰子最小点数为 i */
11             for (int k = 1; k <= face && k <= j; k++)
12                 dp[i][j] += dp[i - 1][j - k];
13 
14     final double totalNum = Math.pow(6, n);
15     List<Map.Entry<Integer, Double>> ret = new ArrayList<>();
16     for (int i = n; i <= pointNum; i++)
17         ret.add(new AbstractMap.SimpleEntry<>(i, dp[n][i] / totalNum));
18 
19     return ret;
20 }
原文地址:https://www.cnblogs.com/mengchunchen/p/10608502.html