简单的冒泡排序

var num = [1, 2, 6, 4, 5, 8, 3, 9, 6, 8]
    var num1 = []
    // 排序
    for (let i = 0; i < num.length; i++) {
      for (let j = 0; j < num.length - i; j++) {
        if (num[j] > num[j + 1]) {
          let temp = num[j];
          num[j] = num[j + 1];
          num[j + 1] = temp;
        }
        document.write('我是第一行' + num[j]);
      }
      // 去重
      if (num1.indexOf(num[i]) === -1) {
        num1.push(num[i])
      }
    }
原文地址:https://www.cnblogs.com/maxiag/p/13487994.html