MT【62】柯西求三角值域

求$sinx(sqrt{cos^2x+24}-cosx)$的范围.

解答:[-5,5]

$$ecause (sinx sqrt{cos^2x+24}-cosxsinx)^2$$

$$le (sin^2x+cos^2x)(cos^2x+24+sin^2x)=25$$



原文地址:https://www.cnblogs.com/mathstudy/p/7535243.html