temporary

#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <vector>
#include <algorithm>
#include <cmath>
using namespace std;
int n, m, s, d;
int e[510][510], cost[510][510], dis[510];
int inf = 999999999;
bool visit[510];
vector<int> pre[510], temppath, path;
int finalcost=inf;
void dfs(int vv) {
    temppath.push_back(vv);
    if (vv == s) {
        int tempcost=0;
        for (int i = temppath.size()-1; i >0; i--) {
            int id = temppath[i], nextid = temppath[i - 1];
            tempcost += cost[id][nextid];
        }
        if (tempcost<finalcost) {
            finalcost = tempcost;
            path = temppath;
        }
        temppath.pop_back();
        return;
    }
    for (int i = 0; i < pre[vv].size(); i++) {
        dfs(pre[vv][i]);
    }
    temppath.pop_back();
}
int main() {
    cin >> n >> m >> s >> d;
    fill(e[0], e[0] + 510 * 510, inf);
    //fill(cost[0], cost[0] + 510 * 510, inf);
    fill(dis, dis+510, inf);
    //fill(visit, visit + 510, false);
    for (int i = 0; i < m; i++) {
        int a, b;
        scanf("%d%d", &a, &b);
        scanf("%d", &e[a][b]);
        e[b][a] = e[a][b];
        scanf("%d", &cost[a][b]);
        cost[b][a] = cost[a][b];
    }
    /*for (int i = 0; i < m; i++) {
        int c1, c2, di, co;
        cin >> c1 >> c2 >> di >> co;
        e[c1][c2] = e[c2][c1] = di;
        cost[c1][c2] = cost[c2][c1] = co;
    }*/
    pre[s].push_back(s);
    dis[s] = 0;
    for (int i = 0; i < n; i++) {
        int u = -1, min = inf;
        for (int j = 0; j < n; j++) {
            if (visit[j] == false &&dis[j]<min) {
                min = dis[j];
                u = j;
            }
        }
        if (u == -1)break;
        visit[u] = true;
        for (int v = 0; v < n; v++) {
            if (visit[v] == false&&e[u][v]!=inf) {
                if (dis[v] > dis[u] + e[u][v]) {
                    dis[v] = dis[u] + e[u][v];
                    pre[v].clear();
                    pre[v].push_back(u);
                }
                else if (dis[v] == dis[u] + e[u][v]) {
                    pre[v].push_back(u);
                }
            }
        }
        dfs(d);
        for (int i = path.size() - 1; i >= 0; i--)
            printf("%d ", path[i]);
        printf("%d %d", dis[d], finalcost);
    }
    return 0;
}
原文地址:https://www.cnblogs.com/masayoshi/p/10867303.html