POJ1995 Raising Modulo Numbers 快速幂

//POJ1995 2020/10/07 23:25
#include <bits/stdc++.h>
using namespace std;

#define ll long long

int T, n, mod;

int add (int x, int y) {
    return (0ll + x + y) % mod; 
}

int mul (int x, int y) {
    return (1ll * x * y) % mod;
}

int fpow (int x, int y) {
    if (x == 0) {
        return 0;
    }
    int ret = 1;
    while (y) {
        if (y & 1) {
            ret = mul (ret, x);
        }
        x = mul (x, x);
        y >>= 1;
    }
    return ret;
}

int main () {
    cin >> T;
    while (T--) {
        int ans = 0;
        cin >> mod >> n;
        for (int i = 1; i <= n; ++i) {
            int x, y;
            cin >> x >> y; 
            ans = add (ans, fpow (x, y));
        }
        cout << ans << endl;
    }
} 

没啥好解释的。

原文地址:https://www.cnblogs.com/maomao9173/p/13779862.html