sprngmvc+restFul 请求报错：404

服务端代码

control类

 1     @RequestMapping(value="getUser",method = RequestMethod.POST)
 2     @ResponseBody
 3     public User getUser(HttpServletRequest request){
 4         String name = request.getParameter("name");
 5         String age = request.getParameter("age");
 6         User user = new User();
 7         user.setPassWord("123123");
 8         user.setUserName("asdasd");
 9         return user;
10     }

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spring核心控制器

 1     <!--配置Springmvc核心控制器 -->
 2     <servlet>
 3         <servlet-name>springmvc</servlet-name>
 4         <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
 5         <init-param>
 6             <param-name>contextConfigLocation</param-name>
 7             <param-value>classpath:springMVC.xml</param-value>
 8         </init-param>
 9     </servlet>
10     <servlet-mapping>
11         <servlet-name>springmvc</servlet-name>
12         <url-pattern>*.action</url-pattern>
13     </servlet-mapping>

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客户端代码

 1 import com.alibaba.fastjson.JSONObject;
 2 import org.apache.http.HttpResponse;
 3 import org.apache.http.client.ClientProtocolException;
 4 import org.apache.http.client.methods.HttpPost;
 5 import org.apache.http.entity.StringEntity;
 6 import org.apache.http.impl.client.DefaultHttpClient;
 7 import org.apache.http.util.EntityUtils;
 8 import org.junit.Test;
 9 
10 import java.io.IOException;
11 
12 public class HttpclientTest {
13     @Test
14     public void httpReqUrl()
15             throws ClientProtocolException, IOException {
16         String url = "http://localhost:8080/ssm/user/getUser";
17         JSONObject json = new JSONObject();
18         DefaultHttpClient httpClient = new DefaultHttpClient();
19         HttpPost method = new HttpPost(url);
20         // 接收参数json列表
21         JSONObject jsonParam = new JSONObject();
22 
23         StringEntity entity = new StringEntity(jsonParam.toString(), "utf-8");//解决中文乱码问题
24         entity.setContentEncoding("UTF-8");
25         entity.setContentType("application/json");
26         method.setEntity(entity);
27 
28         HttpResponse result = httpClient.execute(method);
29         // 请求结束，返回结果
30         String resData = EntityUtils.toString(result.getEntity());
31         JSONObject resJson = json.parseObject(resData);
32         System.out.printf(":::"+resJson.toString());
33     }
34 }

View Code

调用报错：http.404

报错原因：服务端配置的核心控制器，只拦截以 “.action”结尾的请求

解决方案：将服务端核心控制器配置“<url-pattern>*.action</url-pattern>”改为“<url-pattern>/</url-pattern>”