# append() 追加 【在原来值最后追加】 test = [1,2,3,[88,99],'abc'] test.append('99') print(test) [1, 2, 3, [88, 99], 'abc', '99']
# clear() 清空 test = [12, '好', 'abc'] test.clear() print(test) []
# copy() 浅拷贝 test = [12, '好', 'abc'] v = test.copy() print(v) [12, '好', 'abc']
# count() 计算出指定元素出现的次数 test = [12,34,8,56,8,98] v = test.count(8) print(v) 2
# extend() 扩展原来的列表 参数：可迭代对象 test = [12,23,18,19] test.extend([8,66]) print(test) [12, 23, 18, 19, 8, 66] test = [12,23,18,19] test.extend('早上好') print(test) [12, 23, 18, 19, '早', '上', '好']
# index() 根据值获取当前值索引位置(最左边优先) test = [12,22,34,51,22,88] v = test.index(22) print(v) 1
# insert() 在指定位置插入元素 test = [12,22,34,51,22,88] test.insert(0,8) print(test) [8, 12, 22, 34, 51, 22, 88]
# pop() 删除某个值（从最后一个开始删），并获取删除的值 test = [12,22,34,51,22,88] v = test.pop() print(test) print(v) [12, 22, 34, 51, 22] 88 # pop(位置数) 删除指定位置的值 test1 = [12,22,34,51,22,88] v1 = test1.pop(2) print(test1) print(v1) [12, 22, 51, 22, 88] 34
# remove() 删除指定的值，左边优先 test = [12,22,34,51,22,88] test.remove(34) print(test) [12, 22, 51, 22, 88]
ps: 删除的方法 pop() remove() del() del test[2:5] clear()
# reverse() 将当前列表反转 test = [1,2,3,4,5] test.reverse() print(test) [5, 4, 3, 2, 1]
# sort() 排序 （从小到大） test = [2,9,5,7,4,6,0] test.sort() print(test) [0, 2, 4, 5, 6, 7, 9] test1 = [2,9,5,7,4,6,0] test1.sort(reverse=True) #（从大到小） print(test1) [9, 7, 6, 5, 4, 2, 0]