python算法

冒泡排序:

li=[6,4,9,8,2,0,1,3,5,7]
for i in range(len(li)-1):  
 for j in range(i+1,len(li)):
   if li[i] > li[j]:
     tmp = li[j]
     li[j] = li[i]
     li[i] = tmp
print li 

  结果:

[root@db01 xiao]# python paixu2.py 
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
原文地址:https://www.cnblogs.com/machangwei-8/p/8473503.html