poj 3786 Repeater

一道递归构造图形的题,做的时候一直TLE,多想想优化才过的。

 1 #include <stdio.h>
 2 #include <string.h>
 3 char map[2500][2500];
 4 char tplt[6][6];
 5 int n;
 6 void build(int m, int x, int y)
 7 {
 8     int i,j,sum = 1;
 9     for(i = 1; i < m; i++) sum *= n;
10     if(m == 1)
11         for(i = x; i < x+n; i++)
12             for(j = y; j < y+n; j++)
13                 map[i][j] = tplt[i-x][j-y];
14     else for(i = 0; i < n; i++)
15         for(j = 0; j < n; j++)
16             if(tplt[i][j] != ' ')
17                 build(m-1,x+i*sum,y+j*sum);
18 }
19 int main()
20 {
21     int m,i,j,sum;
22     while(scanf("%d",&n),n)
23     {
24         getchar();
25         memset(map,' ',sizeof map);
26         for(i = 0; i < n; i++)
27             gets(tplt[i]);
28         scanf("%d",&m);
29         build(m,0,0);
30         sum = 1;
31         for(i = 0; i < m; i++) sum *= n;
32         for(i = 0; i < sum; i++)
33         {
34             map[i][sum] = '\0';
35             for(j = sum-1; j >= 0; j--)
36                 if(map[i][j] != ' ')
37                 {
38                     map[i][j+1] = '\0';
39                     break;
40                 }
41             printf("%s\n",map[i]);
42         }
43     }
44     return 0;
45 }
原文地址:https://www.cnblogs.com/lzxskjo/p/2661083.html