树:

节点的度:

层次与深度:

有序树和无序树:

树林:

树的存储结构:(结合顺序存储和链式存储)

三种表示方法:

1、双亲表示法:

2、孩子表示法:

3、孩子兄弟表示法:

public class TreeNode{
        private int index;
        private String data;
        private TreeNode leftChild;
        private TreeNode rightChild;
        
        public TreeNode(int index,String data){
            this.index = index;
            this.data = data;
            this.leftChild = null;
            this.rightChild = null;
        }
    }
public class BinaryTree {
    private TreeNode  root = null;
    
    public BinaryTree(){
        root = new TreeNode(1, "A");
    }
    
}

构建二叉树:

   /**
     * 构建二叉树
     *         A
     *     B       C
     * D      E        F
     */
    public void createBinaryTree(){
        TreeNode nodeB = new TreeNode(2, "B");
        TreeNode nodeC = new TreeNode(3, "C");
        TreeNode nodeD = new TreeNode(4, "D");
        TreeNode nodeE = new TreeNode(5, "E");
        TreeNode nodeF = new TreeNode(6, "F");
        root.leftChild = nodeB;
        root.rightChild = nodeC;
        nodeB.leftChild = nodeD;
        nodeB.rightChild = nodeE;
        nodeC.rightChild = nodeF;
    }

求二叉树的高度:

   /**
     * 求二叉树的高度
     * @author Administrator
     *
     */
    public int getHeight(){
        return getHeight(root);
    }
    
    private int getHeight(TreeNode node) {
        if(node == null){
            return 0;
        }else{
            int i = getHeight(node.leftChild);
            int j = getHeight(node.rightChild);
            return (i<j)?j+1:i+1;
        }
    }

求二叉树节点的个数:

   /**
     * 获取二叉树的结点数
     * @author Administrator
     *
     */
    public int getSize(){
        return getSize(root);
    }
    
    
    private int getSize(TreeNode node) {
        if(node == null){
            return 0;
        }else{
            return 1+getSize(node.leftChild)+getSize(node.rightChild);
        }
    }

先序遍历:(A、B、D、E、C、F)

/**
     * 前序遍历——迭代
     * @author Administrator
     *
     */
    public void preOrder(TreeNode node){
        if(node == null){
            return;
        }else{
            System.out.println("preOrder data:"+node.getData());
            preOrder(node.leftChild);
            preOrder(node.rightChild);
        }
    }
    
    /**
     * 前序遍历——非迭代
     */
    
    public void nonRecOrder(TreeNode node){
        if(node == null){
            return;
        }
        Stack<TreeNode> stack = new Stack<TreeNode>();
        stack.push(node);
        while(!stack.isEmpty()){
            //出栈和进栈
            TreeNode n = stack.pop();//弹出根结点
            //压入子结点
            System.out.println("nonRecOrder data"+n.getData());
            if(n.rightChild!=null){
                stack.push(n.rightChild);
                
            }
            if(n.leftChild!=null){
                stack.push(n.leftChild);
            }
        }
    }

中序遍历:(D、B、E、A、C、F)

/**
     * 中序遍历——迭代
     * @author Administrator
     *
     */
    public void midOrder(TreeNode node){
        if(node == null){
            return;
        }else{
            midOrder(node.leftChild);
            System.out.println("midOrder data:"+node.getData());
            midOrder(node.rightChild);
        }
    }

后序遍历(D、E、B、F、C、A):

/**
     * 后序遍历——迭代
     * @author Administrator
     *
     */
    public void postOrder(TreeNode node){
        if(node == null){
            return;
        }else{
            postOrder(node.leftChild);
            postOrder(node.rightChild);
            System.out.println("postOrder data:"+node.getData());
        }
    }
原文地址:https://www.cnblogs.com/lzb0803/p/9174568.html