#树#二叉搜索树的最近公共祖先

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
        if(p.val > q.val) {
            TreeNode r = p;
            p = q;
            q = r;
        }
        while(root !=null) {
            if(root.val < p.val) {
                root = root.right;
            }else if(root.val > q.val) {
                root = root.left;
            }else{
                return root;
            }
        }
        return root;

    }
    
}
原文地址:https://www.cnblogs.com/lyr-2000/p/13302908.html