排序算法

堆排序

#include <iostream>
using namespace std;
int tempnum;
void KeepCharacter(int *data,int n,int num)        //保持性质函数,保证是一个大根推;
{
    int left=n*2;
    int right=n*2+1;
    int max;                  //记录最大的数字的位置;
    if(left<=num&&data[n]<data[left])              //比较根与左孩子大小,挑出一个比较大的数
    max=left;
    else
    max=n;
    if(right<=num&&data[max]<data[right])            //比较局部极大值与右孩子,挑出一个最大值
    max=right;
    if(max!=n)
    {
        int temp=data[max];
        data[max]=data[n];
        data[n]=temp;
        KeepCharacter(data,max,num);              //调整后子树有可能不满足性质,应该递归调用;
    }
}

void HeapSort(int *data,int num)
{
    for(int i=num/2;i>=1;i--)              //建堆调用
    KeepCharacter(data,i,num);

    for(int i=num;i>=2;i--)
    {
        int temp=data[1];
        data[1]=data[i];
        data[i]=temp;
        num-=1;
        KeepCharacter(data,1,num);
    }
}

int main()
{
    int num;
    cout<<"Please input the num of data:"<<endl;
    cin>>num;
    cout<<"Please input data:"<<endl;
    int *data=new int[num+1];
    for(int i=1;i<=num;i++)
        cin>>data[i];

    for(int i=num/2;i>=1;i--)              //建堆调用
    KeepCharacter(data,i,num);

    HeapSort(data,num);

    cout<<"After sorted:"<<endl;
    for(int i=1;i<=num;i++)
    cout<<data[i]<<" ";
    cout<<endl;
}

自底向上的归并排序:

import java.util.Scanner;

public class Merge {
	
	private static int[] aux;
	
	public static void sort(int[] a){
		aux = new int[a.length];
		sort(a,0,a.length-1);
	}
	
	public static void mergefun(int[] a,int lo,int mid,int hi){
		int i = lo,j = mid+1;
		for(int k = lo;k <= hi; k++)
			aux[k] = a[k];
		
		for(int k = lo;k <= hi; k++)
			if(i>mid)
				a[k] = aux[j++];
			else if(j>hi)
				a[k] = aux[i++];
			else if(a[i]<a[j])
				a[k] = aux[j++];
			else
				a[k] = aux[i++];
	}
	
	private static void sort(int[] a,int lo,int hi){
		if(hi<=lo)
			return;
		int mid = lo+(hi-lo)/2;
		sort(a,lo,mid);
		sort(a,mid+1,hi);
		mergefun(a,lo,mid,hi);
	}
	
	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		String str = in.nextLine();
		String[] arrdata = str.split(" ");
		int[] data = new int[arrdata.length];
		for(int i = 0;i < arrdata.length; i++)
			data[i] = Integer.parseInt(arrdata[i]);
		sort(data);
		for(int i = 0;i < data.length; i++)
			System.out.print(data[i]+" ");
		System.out.println();
		
	}
}

希尔排序:

package com.sort;

import java.util.Scanner;

public class Shell {
	
	public static void sort(int[] a){
		int n = a.length;
		int h = 1;
		while(h<n/3) h = h*3+1;
		while(h>=1){
			for(int i = h; i < n; i++){
				for(int j = i; (j >= h)&&(a[j]<a[j-h]);j -= h ){
					int temp = a[j];
					a[j] = a[j-h];
					a[j-h] = temp;
				}
			}
			h = h/3;
		}
	}
	
	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		String str = in.nextLine();
		String[] arrdata = str.split(" ");
		int[] data = new int[arrdata.length];
		for(int i = 0;i < arrdata.length; i++)
			data[i] = Integer.parseInt(arrdata[i]);
		sort(data);
		for(int i = 0;i < data.length; i++)
			System.out.print(data[i]+" ");
		System.out.println();
	}
}

快速排序:

package com.sort;

import java.util.Scanner;

public class Quick {
	private static void sort(int[] a,int lo,int hi){
		if(hi<=lo)
			return;
		int j = partition(a,lo,hi);
		sort(a,lo,j-1);
		sort(a,j+1,hi);
	}

	private static int partition(int[] a, int lo, int hi) {
		int i = lo,j = hi+1;
		int v = a[lo];
		while(true){
			while(a[++i]<v)
				if(i==hi)
					break;
			while(v<a[--j])
				if(j==lo)
					break;
			if(i>=j)
				break;
			int temp = a[i];
			a[i] = a[j];
			a[j] = temp;
		}
		int temp2 = a[lo];
		a[lo] = a[j];
		a[j] = temp2;
		return j;
	}
	
	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		String str = in.nextLine();
		String[] arrdata = str.split(" ");
		int[] data = new int[arrdata.length];
		for(int i = 0;i < arrdata.length; i++)
			data[i] = Integer.parseInt(arrdata[i]);
		sort(data,0,data.length-1);
		for(int i = 0;i < data.length; i++)
			System.out.print(data[i]+" ");
		System.out.println();
		
	}
}

计数排序:

对于一个int数组,请编写一个计数排序算法,对数组元素排序。

给定一个int数组A及数组的大小n,请返回排序后的数组。

测试样例:
[1,2,3,5,2,3],6
[1,2,2,3,3,5]

public class CountingSort {
    public int[] countingSort(int[] A, int n) {
        count(A);
        return A;
    }

    public static void count(int[] arr) {
        int min = arr[0];
        int max = arr[0];
        for (int i = 1; i < arr.length; i++) {
            min = Math.min(arr[i], min);
            max = Math.max(arr[i], max);
        }
        int[] countArr = new int[max - min + 1];
        for (int i = 0; i < arr.length; i++) {
            countArr[arr[i] - min]++;
        }
        int index = 0;
        for (int i = 0; i < countArr.length; i++) {
            while (countArr[i]-- > 0) {
                arr[index++] = i + min;
            }
        }
    }
}
桶排序(基数排序):

对于一个int数组,请编写一个基数排序算法,对数组元素排序。

给定一个int数组A及数组的大小n,请返回排序后的数组。保证元素均小于等于2000。

测试样例:
[1,2,3,5,2,3],6
[1,2,2,3,3,5]
public class radixSortTry {
	public int calPos(int data,int k){
		for(int i = 1;i < k; i++){
			data /=10;
		}
		return data%10;
	}
	public int[] radixSort(int[] A,int n){
		ArrayList<ArrayList<Integer>> list = new ArrayList<ArrayList<Integer>>();
		for(int i = 0;i < 10;i++)
			list.add(new ArrayList<Integer>());
		for(int i = 1;i <= 4; i++){
			for(int j = 0;j < n; j++){
				list.get(calPos(A[j],i)).add(A[j]);
			}
			
			int pos = 0;
			for(int j = 0;j<list.size();j++){
				int num = list.get(j).size();
				for(int k = 0;k<num;k++)
					A[pos++] = list.get(j).remove(0);
			}

		}

		return A;
	}
	
	public static void main(String[] args) {
		int[] A = {54,35,48,36,27,12,44,44,8,14,26,17,28};
		radixSortTry t = new radixSortTry ();
		t.radixSort(A, 13);
	}
}

  

态度决定高度,细节决定成败,
原文地址:https://www.cnblogs.com/lxk2010012997/p/3023239.html