瑞士轮做法

#include <iostream>
#include <vector>
 
using namespace std;
 
void merge(vector<int> &arr,int L,int mid,int R)
{
	int *help = new int(R-L+1);
	int p1=L,p2=mid+1,i=0;
	while(p1<=mid && p2<=R)
	{
		help[i++] = arr[p1]>arr[p2] ? arr[p2++] : arr[p1++];
	}
	while(p1<=mid)
		help[i++] = arr[p1++];
	while(p2<=R)
		help[i++] = arr[p2++];
 
	for (int i=0;i<R-L+1;i++)
	{
		arr[L+i] = help[i];
	}
}
void sortprocess(vector<int> &arr,int L,int R)
{
	if (L < R)
	{
		int mid = L + ((R-L)>>2);  //  (L+R)/2
		sortprocess(arr,L,mid);
		sortprocess(arr,mid+1,R);
		merge(arr,L,mid,R);
	}
}
 
void MergeSort(vector<int> &arr,int L,int R)
{
	if (arr.size()<2)
		return;
	sortprocess(arr,L,R);
}
 
 
int main()
{
	vector<int> arr;
	int n,temp;
	cin>>n;  //输入n个数
	for (int i=0;i<n;i++)
	{
		cin>>temp;  //输入数据
		arr.push_back(temp);
	}
 
	MergeSort(arr,0,arr.size()-1);
 
	for(int i=0;i<arr.size();i++)
		cout<<arr[i]<<endl;
 
	system("pause");
	return 0;
 
}

码住了,归并加暴力分解

原文地址:https://www.cnblogs.com/lwt99/p/14008200.html