栈和队列_leetcode199

# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None

class Solution(object):
def rightSideView(self, root):
"""
:type root: TreeNode
:rtype: List[int]
"""

res = []

if not root:
return res

queue = []
queue.append(root)

while queue:
level = []

for i in range(len(queue)):
node = queue.pop(0)
level.append(node.val)

if node.left:
queue.append(node.left)
if node.right:
queue.append(node.right)

res.append(level.pop())
return res
原文地址:https://www.cnblogs.com/lux-ace/p/10547433.html