递归与二叉树_leetcode111

# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None

class Solution(object):
def minDepth(self, root):
"""
:type root: TreeNode
:rtype: int
"""

if not root :
return 0


if not root.left and not root.right:
return 1


if root.left and not root.right:
return self.minDepth(root.left) + 1

if root.right and not root.left:
return self.minDepth(root.right) +1

return min(self.minDepth(root.left),self.minDepth(root.right))+1
原文地址:https://www.cnblogs.com/lux-ace/p/10546774.html