递归与二叉树_leetcode100

# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None

class Solution(object):
def isSameTree(self, p, q):
"""
:type p: TreeNode
:type q: TreeNode
:rtype: bool
"""

if not p and not q:
return True

if not p and q:
return False

if p and not q:
return False

if p.val != q.val:
return False

return self.isSameTree(p.left,q.left) and self.isSameTree(p.right,q.right)
原文地址:https://www.cnblogs.com/lux-ace/p/10546756.html