shell脚本显示每个月的天数实现

#!/bin/bash

month_length()

{

monthD="31 28 31 30 31 30 31 31 30 31 30 31"

echo "$monthD" | awk '{print $'"${1}"'}'

}

read month

days_in=$(month_length $month)

echo $days_in

很简陋,但是我很满意  呵呵

原文地址:https://www.cnblogs.com/luwikes/p/2240868.html