简单的数字图形

代码

#include <iostream>
using namespace std;

int main()
{
    int f = 0, i = 5, j = 5, k;
    int A[26][26];
    for (k = 1; k <= 25; k ++)
    {
        A[i][j] = k;
        if (f == 0)
        {
            if (j == 5 && i != 1)
            {
                i--;
                f = 1;
            }
            else if (i == 1)
            {
                j--;
                f = 1;
            }
            else
            {
                i--;
                j++;
            }
        }
        else
        {
            if (i == 5 && j != 1)
            {
                j--;
                f = 0;
            }
            else if (j == 1)
            {
                i--;
                f = 0;
            }
            else
            {
                i++;
                j--;
            }
        }
    }

    printf("1 -----------------------\n");
    for (i = 1; i != 6; ++i)
    {
        for (j=1; j != 6; ++j)
        {
            printf("%4d", A[i][j]);
        }
        printf("\n");
    }

    i = 5;
    j = 5;
    f = 0;
    for (k = 1; k < 13; k++)
    {
        A[i][j] = k;
        A[6-i][6-j] = 26 - k;
        if (f==0)
        {
            if (j==5)
            {
                i--;
                f=1;
            }
            else
            {
                i--;
                j++;
            }
        }
        else
        {
            if (i==5)
            {
                j--;
                f=0;
            }
            else
            {
                i++;
                j--;
            }
        }
    }

    printf("2 -----------------------\n");
    for (i = 1; i != 6; ++i)
    {
        for (j=1; j != 6; ++j)
        {
            printf("%4d", A[i][j]);
        }
        printf("\n");
    }

    f = 0, i = 1, j = 1, k;
    for (k = 1; k <= 25; k ++)
    {
        A[i][j] = k;
        if (f == 0)
        {
            if (j == 1 && i != 5)
            {
                i++;
                f = 1;
            }
            else if (i == 5)
            {
                j++;
                f = 1;
            }
            else
            {
                i++;
                j--;
            }
        }
        else
        {
            if (j == 5 && i != 1)
            {
                i++;
                f = 0;
            }
            else if (i == 1)
            {
                j++;
                f = 0;
            }
            else
            {
                i--;
                j++;
            }
        }
    }

    printf("3 -----------------------\n");
    for (i = 1; i != 6; ++i)
    {
        for (j=1; j != 6; ++j)
        {
            printf("%4d", A[i][j]);
        }
        printf("\n");
    }

    i = 1;
    j = 1;
    f = 0;
    for (k = 1; k < 13; k++)
    {
        A[i][j] = k;
        A[6-i][6-j] = 26 - k;
        if (f==0)
        {
            if (j==1)
            {
                i++;
                f=1;
            }
            else
            {
                i++;
                j--;
            }
        }
        else
        {
            if (i==1)
            {
                j++;
                f=0;
            }
            else
            {
                i--;
                j++;
            }
        }
    }

    printf("4 -----------------------\n");
    for (i = 1; i != 6; ++i)
    {
        for (j=1; j != 6; ++j)
        {
            printf("%4d", A[i][j]);
        }
        printf("\n");
    }
}

1 -----------------------
25 23 22 16 15
24 21 17 14   7
20 18 13   8   6
19 12   9   5   2
11 10   4   3   1
2 -----------------------
25 23 22 16 15
24 21 17 14   7
20 18 13   8   6
19 12   9   5   2
11 10   4   3   1
3 -----------------------
   1   3   4 10 11
   2   5   9 12 19
   6   8 13 18 20
   7 14 17 21 24
15 16 22 23 25
4 -----------------------
   1   3   4 10 11
   2   5   9 12 19
   6   8 13 18 20
   7 14 17 21 24
15 16 22 23 25
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