bash shell 生成10个随机数,并用冒泡排序法将其升序排序

 1 #!/bin/bash
 2 #__author__:lushenle
 3 #description:Generaye 10 random numbers and sort
 4 #Version:0.0.1
 5 #
 6 declare -a nums
 7 declare -i t
 8 for i in {0..9};do
 9     nums[$i]=$RANDOM
10     echo ${nums[$i]}
11 done
12 
13 for ((i=0;i<${#nums[@]};i++));do
14     for ((j=${#nums[@]}-1;j>i;j--));do
15         if [[ ${nums[j]} -lt ${nums[j-1]} ]];then
16             t=${nums[j]}
17             nums[j]=${nums[j-1]}
18             nums[j-1]=$t
19         fi
20     done
21 done
22 echo ${nums[@]}
原文地址:https://www.cnblogs.com/lushengle/p/7773025.html