C#打开指定目录的文件夹

string path = @"C:\Program Files"
System.Diagnostics.Process.Start(
"explorer.exe", path);

===========打开当前程序的文件夹目录

            string path = Application.StartupPath;
            System.Diagnostics.Process.Start("explorer.exe", path);


原文地址:https://www.cnblogs.com/lstcJaney/p/2290744.html