实现 js 数据类型的判断函数type

  

type = (obj) => {                
              const pass1 = typeof obj
              if (pass1 != 'object') return pass1
              const pass2 = obj == null ? 'null' : Object.getPrototypeOf(obj).constructor.name.toLowerCase()
              return pass2
            }
            console.log(type({"a":"111",a:[1,2,3]}))
//自己 测试了下ok的!0.0
原文地址:https://www.cnblogs.com/love314159/p/7656068.html