c++ 根据某个字符或者字符串分割另外一个字符串

void MySplit(const string& s, vector<string>& v, const string& c)
{
  v.clear();
  string::size_type pos1 = 0, pos2 = s.find(c);
  while (string::npos != pos2)
  {
    v.push_back(s.substr(pos1, pos2 - pos1));

    pos1 = pos2 + c.size();
    pos2 = s.find(c, pos1);
  }
  if (pos1 != s.length())
    v.push_back(s.substr(pos1));
}

原文地址:https://www.cnblogs.com/longma8586/p/13916629.html