asp.net弹出提示与跳转方式

asp.net弹出提示与跳转方式1,页面中显示:
Response.Write(i.ToString ()+"<br>"); 

2,对话框显示:
Page.RegisterStartupScript("msg", "<script>alert('" + _info + "')<" + "/script>");
Response.Write("<script>alert('"+_info+"')<" + "/script>");
 
3.提示之后再跳转:
Response.Write("<script>alert('注册成功');window.location='/employee/stulogsuccess.aspx';<" + "/script>");
注:此方法不可用window.history.back()返回;
 
4.直接跳转:
Response.Redirect("/employee/stulogsuccess.aspx",false);
 
 
5.用js跳转:
Response.Write("<script>window.location='/employee/stulogsuccess.aspx';<" + "/script>");
 
6.带参数跳转:
 Response.Redirect("/Controls/error.aspx?msg="+Server.UrlEncode("提交信息没有成功。请与系统管理员联系。"));
原文地址:https://www.cnblogs.com/longle/p/2072878.html