python寻找突变位点

思路:寻找序列两个序列的差异

s = 'GAGCCTACTAACGGGAT'
t = 'CATCGTAATGACGGCCT'
count = 0
for i in range(len(s)):
    if s[i] != t[i]:
        count +=1
print (count)
原文地址:https://www.cnblogs.com/lmt921108/p/8022991.html