/* 异或的简单应用 a^a = 0 */ class Solution { public: int singleNumber(int A[], int n) { int sum = 0; for(int i = 0 ; i < n ; i++){ sum = sum^A[i]; } return sum; } };
/* 异或的简单应用 a^a = 0 */ class Solution { public: int singleNumber(int A[], int n) { int sum = 0; for(int i = 0 ; i < n ; i++){ sum = sum^A[i]; } return sum; } };