namespace 再练一遍猜拳2
{
class Program
{
static void Main(string[] args)
//首先先随机生成三个数，然后将0,1,2变成剪刀石头布，利用switch case达到，在比较的时候注意当x为0，y为2的时候，出x的获胜。即先判断这一句 x == 0 && y == 2 ，这句成立直接输出，因为后面的是||或者的意思；y获胜也一样，即先判断x == 2 && y == 0这一句，如果不成立再判断下一句。
{
Console.ForegroundColor = ConsoleColor.Green;
while (true)
{
int x, y; string a,b;
Random r = new Random();
x = r.Next(0, 3);
y = r.Next(0, 3);
switch (x)
{
case 0:
a = "剪刀";
break;
case 1:
a = "石头";
break;
case 2:
a = "布";
break;
default:
a = "傻叉";
break;
}
switch (y)
{
case 0:
b = "剪刀";
break;
case 1:
b = "石头";
break;
case 2:
b = "布";
break;
default:
b = "傻叉";
break;
}
Console.WriteLine(a);
Console.WriteLine(b);
if (x > y)
{
if (x== 2 && y == 0)
{
Console.WriteLine("出" + b + "的获胜");
}
else
{
Console.WriteLine("出" + a + "的获胜");
}
}
else if (x < y)
{
if (x == 0 && y == 2)
{
Console.WriteLine("出" + a + "的获胜");
}
else
{
Console.WriteLine("出" + b + "的获胜");
}
}
else
{
Console.WriteLine("平局");
}
Console.ReadLine();
}
}
}
}