sox应用实例:平分一个音频文件

#!/bin/bash

for f in $(ls *.wav)
do
        id=$(basename $f ".wav")
        dur=$(sox $f -n stat 2>&1 | sed -n 's#^Length (seconds):[^0-9]*([0-9.]*)$#1#p' | awk -F "." '{print $1}')
        expr $dur + 0
        mid=$(( $dur / 2 ))
        sox $f ${id}_0_${mid}.wav trim 0 $mid
        sox $f ${id}_${mid}_${dur}.wav trim $mid $dur
done
原文地址:https://www.cnblogs.com/liuyihua1992/p/13167418.html