28 对10个数进行排序

题目:对10个数进行排序

 1    public class _028Compositor {
 2 
 3     public static void main(String[] args) {
 4         compositor();
 5     }
 6 
 7     private static void compositor() {
 8         Scanner scanner = new Scanner(System.in);
 9         int[] a = new int[10];
10         System.out.println("请输入10个整数,数与数之间用空格分开:");
11 
12         // 遍历输入的十个数
13         for (int i = 0; i < 10; i++) {
14             a[i] = scanner.nextInt();
15         }
16 
17         // 对输入的十个数进行简单排序
18         for (int i = 0; i < 10; i++) {
19             for (int j = i + 1; j < 10; j++) {
20                 if (a[i] > a[j]) {
21                     int temp = a[i];
22                     a[i] = a[j];
23                     a[j] = temp;
24                 }
25             }
26         }
27 
28         System.out.println("排序结果为:");
29         // 输出排序结果
30         for (int i = 0; i < 10; i++) {
31             System.out.print(a[i] + " ");
32         }
33     }
34 
35 }
原文地址:https://www.cnblogs.com/liuyangfirst/p/6537945.html