c++基础_时间转换

#include <iostream>
using namespace std;
int main(){
    int n;
    cin>>n;
    int a=0,b=0,c=0;
    if((n/3600)!=0){
         a=n/3600;
        n=n%3600;
        
    }
    if((n/60)!=0){
         b=n/60;
         n=n%60;
    }
    c=n;
    cout<<a<<":"<<b<<":"<<c;
}
原文地址:https://www.cnblogs.com/liushuncheng/p/8654458.html