SQL语句打印四个方向的9 9 乘法表

declare @i int ,@j int  ,@s nvarchar(max)
set @i = 1
while @i <=9
begin
	set @s = ' '
	set @j = 1
	while @j <=@i
		begin
			 set @s += cast(@j as char(1)) + '*' + cast(@i as char(1))
			 set @s += '    '
			 set @j +=1
		end
		print @s
		set @i += 1
end

  

declare @i int ,@j int  ,@s nvarchar(max)
set @i = 1
while @i <=9
begin
    set @s = ''
    set @j = 1
    while @j <=9
        begin
             if @j  >= @i
             begin
                 set @s += cast(@i as char(1)) + '*' + cast(@j as char(1))
                 set @s += '    '
             end
             else
            begin
                    set @s += '       '
            end
             set @j +=1
        end
        print @s
        set @i += 1
end
declare @i int ,@j int  ,@s nvarchar(max)
set @i = 1
while @i <=9
begin
    set @s = ''
    set @j = 1
    while @j <=@i
        begin
             if @j  >= @i
             begin
                 set @s += cast(@i as char(1)) + '*' + cast(@j as char(1))
                 set @s += '    '
             end
             
             set @j +=1
        end
        print @s
        set @i += 1
end
declare @i int ,@j int  ,@s nvarchar(max)
set @i = 1
while @i <=9
begin
    set @s = ''
    set @j = 1
    while @j <=9
        begin
             if @j > 9 -@i
             begin
                 set @s += cast(@i as char(1)) + '*' + cast((10 -@j) as char(1))
                 set @s += '    '
             end
             else
             begin
                 set @s += '       '
             end
             set @j +=1
        end
        print @s
        set @i += 1
end
原文地址:https://www.cnblogs.com/liumengchen-boke/p/6093698.html