1109. Conference 夜

http://acm.timus.ru/problem.aspx?space=1&num=1109

匈牙利算法简单题  好久没写匈牙利算法了 

先让A组 和 B组 尽量多的配对  剩余人数每个人连一根

代码：

#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<vector>
#include<map>
#include<cmath>
#include<queue>
#include<stack>
#include<algorithm>

using namespace std;
const int INF=0x3f3f3f3f;
const int N=1005;
vector<int>negotiate[N];
int f[N];
bool visited[N];
bool dfs(int x)
{//cout<<x<<endl;
    for(unsigned int i=0;i<negotiate[x].size();++i)
    {
        if(visited[ negotiate[x][i] ])
        continue;
        visited[ negotiate[x][i] ]=true;
        if(f[ negotiate[x][i] ]==-1||(dfs( f[ negotiate[x][i] ] )))
        {
            f[negotiate[x][i]]=x;
            return true;
        }
    }
    return false;
}
int main()
{
    //freopen("data.txt","r",stdin);
    int n,m,k;
    while(scanf("%d %d %d",&n,&m,&k)!=EOF)
    {
        for(int i=1;i<=n;++i)
        negotiate[i].clear();
        while(k--)
        {
            int l1,l2;
            scanf("%d %d",&l1,&l2);
            negotiate[l1].push_back(l2);
        }
        memset(f,-1,sizeof(f));
        int tmp=0;
        for(int i=1;i<=n;++i)
        {
            memset(visited,false,sizeof(visited));
            if(dfs(i))
            ++tmp;
        }
        printf("%d\n",n+m-tmp*2+tmp);
    }
    return 0;
}