Bash 脚本 从路径分离出文件夹和文件名

bash to get file name

fspec="/exp/home1/abc.txt" 
filename="${fspec##*/}"  # get filename
dirname="${fspec%/*}" # get directory/path name

other ways

awk

$ echo $fspec | awk -F"/" '{print $NF}'
abc.txt

sed

$ echo $fspec | sed 's/.*///'
abc.txt

using IFS

$ IFS="/"
$ set -- $fspec
$ eval echo ${${#@}}
abc.txt

https://stackoverflow.com/questions/2536046/extract-directory-path-and-filename

answered Mar 29 '10 at 6:30

ghostdog74